Dear student,Let the radius and height of cylinder and cone be r and hCSA of cylinder=2πrhCSA of cone=πrl where l =r2+h2 is the slant height of coneCSA of cylinderCSA of cone=852πrhπrl=852hr2+h2 =85Squaring both sides,4h2r2+h2 =6425100h2=64r2+64h2100h2-64h2=64r236h2=64r2r2h2=3664rh=68=34r:h is 3:4Regards

Pl help fast

D e a r s t u d e n t, L e t t h e r a d i u s a n d h e i g h t o f c y l i n d e r a n d c o n e b e r a n d h C S A o f c y l i n d e r = 2 πrh CSA of cone = πrl where l = \sqrt{r^{2} + h^{2}} is the slant height of cone \frac{CSA of cylinder}{CSA of cone} = \frac{8}{5} \frac{2 πr h}{πr l} = \frac{8}{5} \frac{2 h}{\sqrt{r^{2} + h^{2}}} = \frac{8}{5} Squaring both sides, \frac{4 h^{2}}{r^{2} + h^{2}} = \frac{64}{25} 100 h^{2} = 64 r^{2} + 64 h^{2} 100 h^{2} - 64 h^{2} = 64 r^{2} 36 h^{2} = 64 r^{2} \frac{r^{2}}{h^{2}} = \frac{36}{64} \frac{r}{h} = \frac{6}{8} = \frac{3}{4} r : h is 3 : 4 Regards

View Full Answer