please ans fast step by step  

T w o   c a r s   A   a n d   B   a r e   t r a v e l l i n g   i n   t h e   s a m e   d i r e c t i o n   w i t h   v e l o c i t i e s   v 1     a n d   v 2   ( v 1   >   v 2 ) .   W h e n   t h e   c a r   B   i s   a t   a   d i s tan c e   d   a h e a d   o f   t h e   c a r   A ,   t h e   d r i v e r   o f   t h e   c a r   A   a p p l i e d   t h e   b r a k e   p r o d u c i n g   a   u n i f o r m   r e t a r d a t i o n   a   T h e r e   w i l l   b e   n o   c o l l i s i o n   w h e n ( a )     d   <   v 1   -   v 2 2 2 a                           ( b )     d   <   v 1 2   -   v 2 2 2 a                                             ( c )     d   >   v 1   -   v 2 2 2 a                                                                                   ( d )         d   >   v 1 2   -   v 2 2 2 a  

Dear Student

For the car A,

Initial velocity = v 1

Retardation = a

Distance it has to travel to avoid collision is = d

For car B,

Velocity of travel = v 2

Now,

The relative velocity of A with respect to B is, u = v 1 – v 2 .

The relative velocity becomes zero for the trains to avoid collision. That is, final relative velocity is, v = 0  [at this moment the cars have equal velocity]

Now, using, v 2 = u 2 – 2as  [negative sign appears since a is retardation]

=> 0 = (v 1 – v 2 ) 2 – 2ad

=> d = (v – v 2 ) 2 /(2d)

So to avoid collision d should be greater than d >(v – v 2 ) 2 /(2d)

Option d is right

Regards

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