Please answer 25th qustion and please answer to this particular question

Here, AB||CD & transversal PQ intersects them at P &  Q.

∠PQR=∠APQ

[Alternate interior angles]

 

X=50°   [∠APQ=50°(given)]

∠PQR=50°

 

AB||CD & transversal PR intersects them at P &  R.

∠APR=∠PRD (alternate interior angles)

(∠APQ+∠QPR)=127°

[∠PRD=127°(given)]

 

50°+y= 127°

Y= 127- 50=77°

 

Hence, x= 50° & y= 77°

  • 0
What are you looking for?