Please answer 2a question

Dear Student,

$2x^2-3x-5$ can be the factor of $10x^4-29x^3+29x-10$ only when on division the remainder must be ZERO.

Thus, dividing $10x^4-29x^3+29x-10$ by $2x^2-3x-5$, we get,



Since, on division, the remainder is ZERO, hence we can say that $2x^2-3x-5$ is a factor of $10x^4-29x^3+29x-10$.

Or, we can also say that $(2x^2-3x-5) (5x^2-7x+2) = 10x^4-29x^3+29x-10$

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