Please answer fast... Using the principle of mathematical induction prove that 3n ⩾ 2n Share with your friends Share 0 Aditi Jain. answered this Dear Student,We have to prove 3n≥2n using mathematical induction.As 3≥2, thus, 3n≥2n holds for n=1.Let,3n≥2n holds for n=ki.e. 3k≥2kNow, we have to show that 3n≥2n holds for n=k+1Consider 3k+1=3k×3≥2k×3 As 3k≥2kBut 2k×3≥2k×2 [As 3>2]⇒3k+1≥2k+1Thus, 3n≥2n holds for n=k+1and hence, 3n≥2n ∀n∈ℕRegards 0 View Full Answer