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Using the principle of mathematical induction prove that
3n   2n

Dear Student,We have to prove 3n2n using mathematical induction.As 32, thus, 3n2n  holds for n=1.Let,3n2n holds for n=ki.e. 3k2kNow, we have to show that 3n2n holds for n=k+1Consider 3k+1=3k×32k×3        As 3k2kBut 2k×32k×2                                 [As 3>2]3k+12k+1Thus, 3n2n holds for n=k+1and hence, 3n2n nRegards

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