Please answer it quickly.
Dear student,
4) In the given triangle,
Sum of angles of the triangle is 180°
So, angle A + angle B + angle C = 180°
50° + 70° + angle ACB = 180°
Angle ACB = 180° - ( 50° + 70° )
Angle ACB = 60°
And we know, Angle ACB + Angle ACD = 180°.....( Linear pair)
angle ACD = 180° - 60° = 120°
For remaining questions please post again in separate thread.
Regards.
4) In the given triangle,
Sum of angles of the triangle is 180° So, angle A + angle B + angle C = 180°
50° + 70° + angle ACB = 180°
Angle ACB = 180° - ( 50° + 70° )
Angle ACB = 60°
And we know, Angle ACB + Angle ACD = 180°.....( Linear pair)
angle ACD = 180° - 60° = 120°
For remaining questions please post again in separate thread.
Regards.