Please answer my following questions as fast as possible-

1. A hammer exerts a force of 1.5 N on each of the two nails A and B.The area of cross section of tip of nail A is 2mm² while that of a nail B is 6mm². Calculate the pressure on each nail in Pascal.

2. A vessel contains water up to height of 1.5m. taking the density of water 1000kg m-3,acceleration due to gravity 9.8 m s-2and area of the base vessel 100 cm2,calculate :(a) the pressure and (b) the thrust at the base of vessel.

3. The area of base of a cylindrical vessel is 300cm2.Water (density = 1000kgm-3) is poured into it up to a depth of 6 cm. Calculate: (a) the pressure, (b) the thrust of water on the base. (g = 10 ms-2).

4. (a) Calculate the height of the water coloumn which will exert on its base the same pressure as the 70 cm column of mercury. Density of mercury is 13.6g cm-3.

5. a simple u tube contains mercury to the same level in both of its arms . If water is poured to a height of 13.6 cm in one arm , how much will be the rise in the mercury level in the other arm ?

Given : density of mercury = 13600 kg m-3 and the density of water =1000 kg m-3.

Please do it as early as possible.......

1.kindly refer to the following link for the similar query,
https://www.meritnation.com/ask-answer/question/a-force-of-1-5-n-on-each-of-the-two-nails-a-and-b-the/fluids/5747455

2) 
Pressure is given by:P = hρgwhere h is the height or depth of the liquidρ is the density of the liquidg = acceleration due to gravity = 9.8 m/s2 = 980 cm/s2h = 1.5 mρ = 1000 kg/m3P  = 1.5×1000×9.8 P = 14700 papressue = forceareathrust = force= pressure×area = 14700×100×10-4= 147 N

3) 
h = 6 cm = 0.06 mPressutre = p = hρgp = 0.06×1000×9.8 p = 588 paForce = pressue ×areaarea = 300 cm2 = 300×10-4m2force = 588×300×10-4force = 17.64 N


4) Height = 70 cm = 0.07 m
ρ = 13.6 g/cm3 = 13.6×103  kg/m3Pressure p = hρgp = 0.07×13.6×103 ×9.8p = 93296 pa

​5) Kindly refer the following link.
https://www.meritnation.com/ask-answer/question/a-simple-u-tube-contains-mercury-to-the-same-level-in-both-o/laws-of-motion/3311988

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A1.

F=1.5/10=15/10N A of nail A=2mm^2 =2/1000X1000m^2 =2/1000000m^2

P on nail A=F/A =15/10*1000000/2 =7.5X10^5 Pa

A of nail A=6mm^2 =6/1000X1000m^2 =6/1000000m^2

P on nail A=F/A =15/10*1000000/6 =2.5X10^5 Pa

I have the same physics text book...

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