The ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides.
By this theorem ar(?ABC)/ar(?DEF)=(AC)?/(DF)? =(19)?/(8)? =361/64
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Pranayani answered this
The ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides. By this theorem ar(ABC)/ar(DEF)=(AC)^2/(DF)^2 =(19)^2/(8)^2 =361/64
