Please answer question 5

5) Find the zeroes of the polynomial (2x ³ + 5x ² – 9x – 18), if it is given that the product of its two zeroes is –3.

Solution,

=> 2x? + 5x? - 9x - 18 =0

=> 2x? - 4x? + 9x? -18x + 9x - 18 =0

=> 2x?(x-2) + 9x(x-2) + 9(x-2) = 0

=> (x-2) (2x? +9x +9) = 0
=> (x-2) ( 2x? +3x +6x + 9) = 0
=> (x-2) (x+3) (2x +3) = 0

Therefore, zeroes of the polynomials equal to x = 2, - 3 and - 3/2