Please answer these questions fast. Q21. In Figure 12. ∠ BCD = ∠ ADC and ∠ ACB = ∠ BDA. Prove that AD = BC and ∠ A = ∠ B. ∆ ABC and ∆ ABD are two triangles on the same base AB, If line segment CD is bisected by Q22. AB at O. Show that ar (ABC ) = ar (ABD) Express x = 3y in the form ax + by + c = 0 and indicate the value of a, b and c. Write two solutions of the equation. Share with your friends Share 0 Shruti Tyagi answered this Dear student, Question 21) ∠ACB =∠BDA -- (given) ∠ADC = ∠BCD --(given)CD = CD --(common) So ∆ACD≅∆BDC by AAS congruency rule ⇒ AD=BC --(CPCT) ⇒∠A =∠B --(CPCT) Question 22) Regards 0 View Full Answer