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Dear Student

M a g n e t i c I n d u c t i o n B a t t h e c e n t r e o f l o o p d u e t o c u r r e n t I f l o w i n g i n l o o p i s B = \frac{μ_{o} I}{2 R} N o w m a g n e t i c m o m e n t M = I \vec{A} = I {πR}^{2} So \frac{B}{M} = \frac{\frac{μ_{o} I}{2 R}}{{IπR}^{2}} = \frac{μ_{o} I}{2 R} \times \frac{1}{{IπR}^{2}} = \frac{μ_{o}}{2 {πR}^{3}}

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