Please answer this probability quickly
Dear Student,
Let A be the event that team A wins the tournament.
Let B be the event that team B wins the tournament.
Let C be the event that team C wins the tournament.
According to the question, it is given that P(A)=0.6.
Here A,B and C are mutually exclusive events. That is why the sum of probabilities of these events is 1.
i.e P(A)+P(B)+P(C)=1
i.e P(B)+P(C)=0.4
Now it is also given that P(B) and P(C) is greater than 0.
Now, P(B)=0.4-P(C)
Since P(C)>0, P(B) will be less than 0.4.
Hence, the correct answer is option B.
Regards.
Let A be the event that team A wins the tournament.
Let B be the event that team B wins the tournament.
Let C be the event that team C wins the tournament.
According to the question, it is given that P(A)=0.6.
Here A,B and C are mutually exclusive events. That is why the sum of probabilities of these events is 1.
i.e P(A)+P(B)+P(C)=1
i.e P(B)+P(C)=0.4
Now it is also given that P(B) and P(C) is greater than 0.
Now, P(B)=0.4-P(C)
Since P(C)>0, P(B) will be less than 0.4.
Hence, the correct answer is option B.
Regards.