Please answer this question Find x Share with your friends Share 0 Josepaul Paulachan answered this Dear Student∠EAO = 35°O is the center of a circleTherefore OA = OE ( radius )And we know that angle opposite to equal sides are equal.therefore ∠EAO =∠AEO = 35°∠ CAE = ∠AEO =35° ( alternate opposite angles)∠CEA =∠OAE = 35° (alternate opposite angles)Now in △AOE ∠EAO +∠AOE +∠AEO = 180° (angle sum property)35+∠AOE +35 =180∠AOE = 180 -70∠AOE =110°Now consider quadrilateral ACEO∠ACE +∠CEA+∠AEO+∠EOA+∠OAE+∠EAC =360°x+35+35+110+35+35 =360x =110° Regards 0 View Full Answer Bhavyaa Singh answered this Answer is 70? 0
