Please answer this question......

Dear Student,

RPT=RSP By alternate segment theoremPQRS is a cyclic quadrilateralRQP+RSP=180° .....iAlso, T'PT is a straight lineT'PR+RPT=180° .....iiEquating i and ii we getRQP+RSP=T'PR+RPTRQP=T'PR RPT=RSP

Regards!

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