# please answer this

Please find below the solution to the asked query:

$\mathrm{We}\mathrm{have}\phantom{\rule{0ex}{0ex}}\mathrm{f}\left(\mathrm{x},\mathrm{y}\right)={\mathrm{x}}^{2}-{\mathrm{y}}^{2}\phantom{\rule{0ex}{0ex}}\frac{\partial \mathrm{f}}{\partial \mathrm{y}}\left(2,\mathrm{y}\right)=\frac{\partial \mathrm{f}}{\partial \mathrm{y}}\left({2}^{2}-{\mathrm{y}}^{2}\right)=-2\mathrm{y}\phantom{\rule{0ex}{0ex}}\mathrm{Hence}\mathrm{slope}\mathrm{at}\left(2,1,3\right)\mathrm{is}-2\times 1=-2\left[\mathrm{Answer}\right]$

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