En = -1312 n2 kJE2 = -1312 22kJE3 = -1312 32kJE2-E3 = -1312 22 - -1312 32 = -1312 14 -19 = -1312 × 536 = -182 22 kJ Thus the energy required to excite an electron from 2nd to third level is - 182 22 kJ

Please answer

E_{n} = \frac{- 1312}{n^{2}} k J E_{2} = \frac{- 1312}{2^{2}} k J E_{3} = \frac{- 1312}{3^{2}} k J E_{2} - E_{3} = [\frac{- 1312}{2^{2}}] - [\frac{- 1312}{3^{2}}] = - 1312 [\frac{1}{4} - \frac{1}{9}] = - 1312 \times \frac{5}{36} = - 182.22 k J

Thus the energy required to excite an electron from 2nd to third level is - 182.22 kJ

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