# Please anybody ! I need the answer of parts b,c, and d. Thank you

b) The proportional

**constant**k is called the

**spring constant**. It is a measure of the

**spring's stiffness**. When a

**spring**is stretched or compressed, so that its length changes by an

**amount**x from its equilibrium length, then it exerts a force F = -kx in a direction towards its equilibrium position.

So from tbale of measurement

for each F = 100g there is length change of 1 cm

k = F/x = mg/x = 100 x (1000dyne/g)/1 = 10

^{5}dynes/cm

c) Length of spring when carrying load 420 g

so compression length = F/k = 420 x (1000dyne/g)/10

^{5}dynes/cm = 4.2 cm

So length of spring = 20 - 4.2 = 15.8 cm

d) F = kx = 10

^{5}dynes/cm x (20-13.2) = 6.8 x10

^{5}dynes

m =6.8 x10

^{5}dynes/1000dyne/g = 680 g

Regards

**
**