Please do no.8 Share with your friends Share 0 Varun Rawat answered this y2 - z2 + 2xy - 2xz=y+zy-z + 2xy-z=y-zy+z+2x=2x+y+zy-zSo, the other factor is y-z. 0 View Full Answer S Ramaratnam answered this y(2x+y+z) = 2xy +y2 +yz y2 - z2 + 2xy -2xz = y2 - z2 + 2xy -2xz +yz - yz y2 + 2xy + yz - yz -z2 -2xz y(2x+y+z) -z(y+z+2x) = (y-z)(2x+y+z) So dividing the original expression by 2x +y +z we would get y-z 0
