Please explain the formation of D-glucopyranose from D-glucose.
Dear student,
The straight chain structure of D glucose can form hemiacetal, a cyclic structure in an aqueous solution. In this type of reaction of acetal formation, a alcohol forms a tetrahedral intermediate compound when reacted with an aldehyde. In the process of the ring formation of glucose, The hydroxyl group which acts as nucleophile reacts with anomer carbonyl group from either the below or above the plane of the ring which is being formed. Thus, it leads to the formation of two stereoisomers
1) β-D-glucopyranose
2)α -D-glucopyranose
The reaction is shown below
Regards
The straight chain structure of D glucose can form hemiacetal, a cyclic structure in an aqueous solution. In this type of reaction of acetal formation, a alcohol forms a tetrahedral intermediate compound when reacted with an aldehyde. In the process of the ring formation of glucose, The hydroxyl group which acts as nucleophile reacts with anomer carbonyl group from either the below or above the plane of the ring which is being formed. Thus, it leads to the formation of two stereoisomers
1) β-D-glucopyranose
2)α -D-glucopyranose
The reaction is shown below
Regards