Please explain this sum
Dear Student
In triangle APC and triangle AQB,
AP = AQ (given)
<A = <A (common)
AC = AB (given)
so, triangle APC congruent triangle AQB
so CP = BQ (by CPCT) [proved]
Regards
In triangle APC and triangle AQB,
AP = AQ (given)
<A = <A (common)
AC = AB (given)
so, triangle APC congruent triangle AQB
so CP = BQ (by CPCT) [proved]
Regards