# Please give answer of c Dear student,

If work done by external forces acting on a body is zero and all the internal forces are consider,then total mechanical energy of body remains conserved.
ui + Ki = uf +Kt
At point A,KEi = 0
ui=mgH
At point B,ut = 0
Ktf = 1/2 mv2
putting the value of V
K= 1/2m(2gh)
kEt = mgH   ( TE = Kf + ut = mgH)

V2 = u2 + 2gH
V2 = 0 + 2gH
V = root over of 2gH
So,the initial potential energy was mgH and final kinetic energy also comes out to be mgH.
Hence,it is proved that the kinetic energy of freely falling body on reaching the ground is nothing but transformation of its initial potential energy.

Regards,

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Kinetic energy is the energy an object has because of its motion.
If we want to accelerate an object, then we must apply a force. Applying a force requires us to do work. After work has been done, energy has been transferred to the object, and the object will be moving with a new constant speed. The energy transferred is known as kinetic energy, and it depends on the mass and speed achieved.
When a body falls without any restriction, the initial energy (potential; because by the term 'potential', we mean the capabilities of someone or something; something which the object already possesses) gets directly converted into Kinetic Energy. With that being said, we conclude that Kinetic Energy is directly proportional to Potential Energy.
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