As per the question,
Potential provided by primary= 200V
V of secondary = 20V
20V is the final potential obtained which will run the 20ohm resistor
So R= 20ohm
I=V/R = 20 V/20ohm = 1 A
Now efficiency of a transformer is given by,
n = Vs x Is/Vp x Ip that is output/input
80/100 = 20*1/200*Ip
Ip= 1/8
Therefore current drawn by the primary of a transformer is 0.125A.