Please help me out
Q2. Construct a PQR in which QR = 6 cm, PQ = 4.4 cm and PR = 5.3 cm. Draw the bisector of .
Dear Student,
Please find below the solution to the asked query:
We follow these steps to construct required triangle and angle bisector :
Step 1 : Draw a line PQ = 4.4 cm
Step 2 : Take radius of 5.3 cm and center ' P ' draw an arc and take radius of 6 cm and center ' Q ' draw another arc and that arc intersect previous arc at ' R ' .
Step 3 : Join PR and QR and we get required triangle PQR .
Step 4 : Take any radius ( Less than half of PQ ) and center ' P ' draw an arc that intersect line PQ and PR at ' A ' and ' B ' respectively .
Step 5 : With same radius ( Same as we take in step 4 ) and center ' A ' and ' B ' draw arcs and these arcs intersect at ' C ' .
Step 6 : Join PC and extend that so it will meet QR at ' S ' , So PS is angle bisector of P .
Hope this information will clear your doubts about topic.
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.
Regards
Please find below the solution to the asked query:
We follow these steps to construct required triangle and angle bisector :
Step 1 : Draw a line PQ = 4.4 cm
Step 2 : Take radius of 5.3 cm and center ' P ' draw an arc and take radius of 6 cm and center ' Q ' draw another arc and that arc intersect previous arc at ' R ' .
Step 3 : Join PR and QR and we get required triangle PQR .
Step 4 : Take any radius ( Less than half of PQ ) and center ' P ' draw an arc that intersect line PQ and PR at ' A ' and ' B ' respectively .
Step 5 : With same radius ( Same as we take in step 4 ) and center ' A ' and ' B ' draw arcs and these arcs intersect at ' C ' .
Step 6 : Join PC and extend that so it will meet QR at ' S ' , So PS is angle bisector of P .
Hope this information will clear your doubts about topic.
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.
Regards