# Please...help me to solve the question...I just want step by step solution and calculation n cancellation of final equation.

Mass of stone, m = 1 kg

Mass of Earth, M = 6 × 10

^{24}kg

Now, gravitational force of attraction, F = G M m/R

^{2}

Here, R = Radius of earth = 6. 4 × 10

^{6 }m

G = Gravitational constant = 6.67 × 10

^{-11}N m

^{2}/kg

^{2}

Put the values in the equation, F = 9.8 N ( simply solving the equation )

(a) Acceleration produced by stone = F/Mass of stone

(as we know that F = ma) We have used this formula

a = 9.8 / 1 ( we have already calculated force and mass of stone is given in question )

a = 9.8 m/s

^{2}

(b) Acceleration produced in Earth = F/Mass of Earth ( again we are using F = ma)

a = 9.8/6 × 10

^{24}(solving this)

a = 1.63 × 10

^{-24 }m/s

^{2 }[when 10

^{24}moved from denominator to numerator, it becomes 10

^{-24}]

Hope it us clear now. Please let us know in case you are finding problems with calculations also.

Regards

**
**