Please see the circumstances properly: Don't assume GOE as a straight line till it is not given so. As GOE is not given as a staright line,we have to say that: OF OE OD OC OB OA OG are just rays. If there 2 rays from 1 common vertex we can't tell that it forms a straight line. Thus, OG and OE may not form a straight line. ∠COE and ∠BOG are consecutive integral multiple of 10. Like: (20,30) ; (70,80) The pair should be of integers Not like: (12,13) which can be divisible by 10 as (1.2, 1.3) OA bisects angle BOG OD bisects angle COE Please be very specific about the conditions. As I have got answer to this same query twicw by 2 different experts I have seen that they don't go through or match with the circumstances. I have checked the diagram 5 times from the place from where I copied. Share with your friends Share 0 Neha Sethi answered this Dear student Since ∠COE and ∠BOG are consecutive multiples of 10°So, Let ∠COE=10x and ∠BOG=10x+10°Since OA bisects ∠BOG∴∠AOB=∠AOG=12∠BOG=5x+5°Since OD bisects ∠COE∴∠COD=∠DOE=12∠COE=5xGiven: ∠BOC=∠COD4+90°=5x4+90°and, ∠GOF=3∠BOG=310x+10=30x+30Now,∠BOG+BOC+COE+EOF+GOF=360 [Complete angle]⇒10x+10+5x4+90°+10x+70+30x+30=360⇒50x+5x4=160⇒200x+5x4=160⇒205x=640⇒x=640205⇒x=12841Please recheck your question. Post the image from the book. Regards 1 View Full Answer