Please solve 26:

26. Let the quadratic equation jx²+(j-3)x+1=0 has two equal roots for two values of j. If these two values of j are A and M, with A<M, then the value of (tan^-1 A+tan^-1M) equals:


$$\begin{gathered} \left(\mathrm{A}\right) \mathrm{\pi }-{\tan }^{-1}\left(\frac{5}{4}\right) \left(\mathrm{B}\right) {\tan }^{-1}\left(\frac{-5}{4}\right) \\ \left(\mathrm{C}\right) \mathrm{\pi }+{\tan }^{-1}\left(\frac{5}{4}\right) \left(\mathrm{D}\right) {\tan }^{-1}\left(\frac{5}{4}\right) \end{gathered}$$