Please solve 5 (a) immediately: Question 5 (a) Rahim scored 32% marks in an examination and filled by 12 marks. Mohan scored 42% and got 28 marks more then the minimum pass marks. Find the maximum marks and pass percentage of marks. Share with your friends Share 1 Varun Rawat answered this Let the minimum marks needed to pass the exam = xLet the maximum marks = yScore of Rahim = 32% of y = 32y100Now, Rahim failed by 12 marks.So, 32y100 + 12 = x .....1Score of Mohan = 42% of y = 42y100Now, Mohan got 28 marks more than minimum marks to pass.So, 42y100 - 28 = x .....2comparing 1 and 2, we get32y100 + 12 = 42y100 - 28 ⇒10y100 = 40⇒y = 400Put the value of y in 1, we get32 × 400100 + 12 = x⇒x = 140maximum marks = 400Pass % = 140400×100% = 35% 0 View Full Answer Mukund Kumar Pathak answered this Maximum marks can be 400 And Passing marks can be 140 0
