Please solve from 2007 I have exam
2007
1. Salts A,B, C, D & E undergo reaction (i) to (v) respectively. Identify the anion present in each salt.
i] When AgNO3 solution is added to a soln. of A, a white precipitate, insoluble in dilute nitric acid, is formed.
ii] Addition of dil. HCl to B produces a gas which turns lead acetate paper black.
iii] When a freshly prepared solution of FeSO4 is added to a soln, of C and cone. H2SO4 is gently poured from the side of the test-tube, a brown ring is formed.
iv] When dil, H2SO4 is added to D a gas is produced which turns acidified K2Cr2O7 soln. from orange to green.
v] Addition of dil, HC to E produced an effervescence. The gas produced turns lime water milky but does not effect acidified K2Cr2O7 soln.
2. How will the addition of barium chloride soln help to distinguish between dil. HCl & dil H2SO4.
Dear student
[2007]
The first question is answered below :
(i) A—Chloride,
(ii) B—Sulphide,
(iii) C—Nitrate,
(iv) D—Sulphite,
(v) E—Carbonate.
We know that AgCl. is a white precipitate, which is insoluble in nitric acid, so the salt A isAgCl, and the anion is Chloride.
We know that hydrogen sulphide is the gas which turns lead acetate paper black. so the salt B hydrogen sulphide and anion is Sulphide.
We know that brown ring test is given by the NO3- anion.
Sulfur dioxide, turns acidified potassium dichromate paper from orange to green, so the anion is Sulphite.
Carbon dioxide gas turns lime water milky, so here than anion is Carbonate,
Please post remaining questions separately.
Regards
[2007]
The first question is answered below :
(i) A—Chloride,
(ii) B—Sulphide,
(iii) C—Nitrate,
(iv) D—Sulphite,
(v) E—Carbonate.
We know that AgCl. is a white precipitate, which is insoluble in nitric acid, so the salt A isAgCl, and the anion is Chloride.
We know that hydrogen sulphide is the gas which turns lead acetate paper black. so the salt B hydrogen sulphide and anion is Sulphide.
We know that brown ring test is given by the NO3- anion.
Sulfur dioxide, turns acidified potassium dichromate paper from orange to green, so the anion is Sulphite.
Carbon dioxide gas turns lime water milky, so here than anion is Carbonate,
Please post remaining questions separately.
Regards