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D e a r S t u d e n t, W e k n o w t h a t i n f l u i d m e c h a n i n c s, P + \frac{1}{2} ρ v^{2} + ρ g h = c o n s \tan t S o w e w i l l w r i t e t h e s a m e e q u a t i o n f o r t h e t o p a n d p o i n t f r o m w h e r e w a t e r i s f l o w i n g . S o h = 0.5 m g = 10 m / s^{2} ρ = 1000 k g / m^{3} P_{0} + \frac{20 X 10}{0.5} + 0.5 X 1000 X 10 + 0 = P_{0} + \frac{1}{2} (1000) v^{2} O n s o l v i n g t h i s w e g e t v = 3.3 m / s O p t i o n (2) R e g a r d s

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