Dear student, 2H2O -------> 2H2 + O2 (a)2 Vol of H2 = 1 vol of O2 (b) 2500 of H2 = 1/2 x 2500 = 1250 cm3 of O2 (c) (i) P1 = 1 Atm P2 = 2 5 Atm V1 = 2500 V2 = ? P1 V1 = P2 V2 1 x 2500 = 2 5 x V2 V2 = 2500 x 10/25 V2 = 1000 cm3 (c) (ii) If volume of H2 = 1000 cm3 say, temp is T1, V2 = 2500, New temp T2 V1 / T1 = V2 / T2 1000/T1 = 2500/T2 T2/T1= 2500/1000 = 2 5 T2 = 2 5 T1 It must be 2 5 times of original temperature Regards,

Please solve Q. 5

Please solve Q. 5 4. Some of the fertilizers are sodium nitrate NaNO ammonium sulphate and urea CO(NH2) . Which of these contains the highest percentage of nitrogen ? 5. Water decomposes to and H2 under suitable conditions as represented by the equation below : 2 H20 2H2 + 02 (a) If 2500 cm3 of H2 is produced. what volume of 02 is liberated at the same time and under the same conditions of temperature and pressure ? (b) The 2500 crn3 of H2 is subjected to 2 times increase in pressure (temp. remaining constant). What volume will H2 now occupy ? (c) Taking the volume of H2 calculated in 5(b), what changes must be made in kelvin (absolute) temperature to return the volume to 2500 cm3 pressure remaining constant. 4K. Urea is an important nitrogeneous fertilizer, and is sold in 50 kg sacks. What mass of nitrogen is in 9. 10

Dear student,

2H₂O -------> 2H₂ + O₂
(a)2 Vol. of H₂ = 1 vol. of O₂
(b) 2500 of H₂ = 1/2 x 2500 = 1250 cm3 of O₂
(c) (i) P₁ = 1 Atm.
P₂ = 2.5 Atm.
V₁ = 2500
V₂ = ?
P₁ V₁ = P₂ V₂
1 x 2500 = 2.5 x V₂
V₂= 2500 x 10/25
V₂ = 1000 cm3
(c) (ii) If volume of H₂ = 1000 cm3 say, temp. is T₁, V₂ = 2500, New temp. T₂
V₁ / T₁ = V₂ / T₂
1000/T₁ = 2500/T₂
T₂/T₁= 2500/1000 = 2.5
T₂ = 2.5 T₁
It must be 2.5 times of original temperature.

Regards,

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