Please solve question 19

19. A pebble is dropped freely in a well from its top. It takes 20 s for the pebble to reach the water 
 surface in the well. Taking g = 10 m s–2 and speed of sound = 330 m s–1 find : (i) the depth of water surface. 
and (ii) the time when echo is heard after the pebble is dropped.

Dear student. Time taken by the ball to hit the water surface = 20 sec Initial velocity = 0 , acceleration = g = 10m/s² The height of well = H s = ut + 1/2 a t² H = 0 +1/2 * 10*20*20 H = 2000 meter When pebble strikes the surface then sound is produced and it comes to observer by travelling the distance of the well. Velocity of sound = 332 m/s , distance = H = 2000 m time taken by sound to come to observer = t = distance/speed = 2000/332 = 6.02seconds. The sound will be heard after 20 + 6.02 = 26.02 seconds. Regard

  • 1
What are you looking for?