Please solve question 41. Share with your friends Share 0 Anshu Agrawal answered this Dear student, Q41 Here Vrms =200V,XL =50Ω,XC =50Ω,R=25Ω Impedance of the circuit, Z=R2+(XL-XC)2 = 252 (50−50)2= 25Ω Current in the circuit , Irms = VrmsZ =20025 =8A Voltage drop across the inductor is VL =IrmsXL =8A×50Ω=400V Option C is correct Regards 0 View Full Answer