Please solve question 41.

Dear student,

Q41
Here Vrms =200V,XL =50Ω,XC =50Ω,R=25Ω  Impedance of the circuit, Z=R2+(XL-XC)2 = 252 (5050)2= 25Ω  Current in the circuit , Irms  = VrmsZ =20025  =8A  Voltage drop across the inductor is   VL =IrmsXL =8A×50Ω=400V

Option C is correct

Regards

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