Please solve question no 13 and 14 Share with your friends Share 2 Zuhaib Ul Zamann answered this Dear student, Q no 13,For the limit to exist we shall havelimx→1(f(x)-2)=0i.elimx→1f(x)=2Q no 14(1-cos1n)(1-cos1n)(1-cos1n)(1-cos1n...∞=(1-cos1n)12+14+...∞=(1-cos1n)121-12=1-cos1n =2sin212nHence limit equalslim12n→02sin212n12n2×limn→∞12n2×n2=2×14=12 Regards 0 View Full Answer