Please solve question no.33.
Dear Student,
Given that,
a2+b2+c2=125
ab+bc+ca=50
Aa we know,
(a+b+c)2=a2+b2+c2+2(ab+bc+ca)
⇒(a+b+c)2=125+(2*50)
⇒(a+b+c)2=125+100=225
⇒(a+b+c)= =∓15
Regards
Given that,
a2+b2+c2=125
ab+bc+ca=50
Aa we know,
(a+b+c)2=a2+b2+c2+2(ab+bc+ca)
⇒(a+b+c)2=125+(2*50)
⇒(a+b+c)2=125+100=225
⇒(a+b+c)= =∓15
Regards