please solve question no.5(i)(ii) by ising elimination method

2i-ii
2x + (x-y)/6 = 2  #1
x - (2x+y)/3 = 1  #2
for #1 multiplying LHS and RHS by 6
6*2x + (x-y) = 2*6
13x  -y = 12  # 1
for #2 multiplying LHS and RHS by 3
3*x -(2x+y) = 1*3
3x -2x -y  = 3
x -y = 3  #2

13x  -y = 12  # 1
x -y = 3  #2
#1  -  #2
(13x -y) -(x-y) = 12  - 3
12x = 9
x = 3/4
y from #2 is
y  = x -3
y = 3/4 -3 = -9/4
thus x = 3/4 and y = -9/4