# please solve question no.5(i)(ii) by ising elimination method

2x + (x-y)/6 = 2 #1

x - (2x+y)/3 = 1 #2

for #1 multiplying LHS and RHS by 6

6*2x + (x-y) = 2*6

13x -y = 12 # 1

for #2 multiplying LHS and RHS by 3

3*x -(2x+y) = 1*3

3x -2x -y = 3

x -y = 3 #2

13x -y = 12 # 1

x -y = 3 #2

#1 - #2

(13x -y) -(x-y) = 12 - 3

12x = 9

x = 3/4

y from #2 is

y = x -3

y = 3/4 -3 = -9/4

thus x = 3/4 and y = -9/4