Please solve question number 17 and 18

Please solve question number 17 and 18 17. (Jharkhand. Stage-I. 2014-15) A balloon which is ascending at the rate of 12 m/s is 30.4 metre above the ground, When a stone is dropped. After what time the stone will reach the ground? [Take g = 9.8 rn/s?l (2) 36 s (4) 6s (Jharkhand, Stage-I. 2014-15) A ball is dropped from the top of a tower of hoiqht 100 m. Simultaneously. another ball was thrown upward from the bottom of the tower With a speed of 50 m/s (g 10 m/s2), These two balls would cross each other after a time 22. 23 I second (1) (2) 2 seconds (3) 3 seconds (4) 4 seconds (Odisha, Stage-I, 2014-15) m from rest describes distances S,. S?

Dear Student,

Ans17.
When the stone is dropped:

Its initial velocity, u = 12 m/s (upward)

Acceleration, a = -9.8 m/s2 (downward)

Displacement, S = -30.4 m (downward)

Time taken to reach ground, t

Using,

S = ut + ½ at2

=> -30.4 = 12t – 0.5×9.8×t2

=> t = 4 s

Ans4. 4 seconds

P.S. Kindly post separate questions in separate threads.

Regards

  • 0
What are you looking for?