Please solve this equations

Please solve this equations u'Dtdxa cn (V VI : .ramsuv) auö.unoot11J0 öt11DA s! JDqm samugu S u! 6ugonpuoo o q6no.1t0 smou OZ? JO a61Dtp o Jl o•saoumsysau JO sant0A an s! 03ums!szu '13110J0d u! pm3äuuoa uaq/fi og sy mums!SOJ •sagos u! papauuoo s.101S!SöJ OAu uaqm (U : .aaqsuV) i,aq aoums!sa.l s" OL 01 JO t116ua1 ato o JO aoums'saa •V

Dear student,

A) R = ρL/A
L = 1 m
R = 6 ohm
So, according to the formula R is directly proportional to L
So, when R = 6 ohm then L is 1 m accordingly when L = 70 cm = 0.7 m then
R = 0.7 × 6
R = 4.2 ohm

B) Let the two unknown resistors be R1 and R2
According to question,
Req (in series) = 80 ohms
So, R1 + R2 = 80
R1 = 80 - R2      --------- (1)
Further,
Req (in parallel) = 20 ohms
 Req = R1 × R2/( R1 + R2)
From (1)
20 = (80 - R2) R2/ 80
1600 = 80 R2 - R22
R22 -80 R2 + 1600 = 0
On solving we get, R2 = 40 and 40
Therefore, the two resistors are 40 ohm each

Hope this information will clear your doubts about topic.

For more queries just ask in a separate thread here on the forum and our experts will try to help you out as soon as possible.

Regards

 

  • 1
What are you looking for?