Please solve this.
How to find the breadth of a rectangle whose length is double of its breadth and perimeter is 720m.
Let the breadth be x
Then length be 2x ( according to the question)
Perimeter of a rectangle= 2(l+b)
By substituting the values,
2(2x+x)=720
2*3x=720
3x= 720/2
3x=360
x=360/3
=120
So Breadth of the rectangle is 120 m