Please solve this physics question of chapter motion

Dear student




Let the length of the train be ‘L’.

As it crosses the point, the initial velocity can be taken as ‘u’ and final velocity as ‘v’.

So, v² = u² + 2aL

=> v² – u² = 2aL ……………(1)

Suppose the velocity with which the midpoint crosses that certain point be v^/. In this case the distance traveled is L/2.

So,

(v^/)² = u² + 2a(L/2)

=> (v^/)² = u² + ½ × (v² – u²) [using (1)]

=> (v^/)² = (v² + u²)/2

=> v^/ = {(v² + u²)/2}^1/2

This is the velocity of the midpoint of the train with which it crosses that point.



with regards