Please solve this problem How do astronauts communicate on the surface of moon in the absense of any atmosphere - Physics - Propagation of Sound Waves

Question

Please solve this problem
H o w   d o   a s t r o n a u t s   c o m m u n i c
a t e   o n   t h e   s u r f a c e   o f
  m o o n     i n   t h e   a b s e n s e
  o f   a n y   a t m o s p h e r e   ?  
Y o u   s e t   y o u r   w a t c h   b y
  t h e   s o u n d   o f   a   d i s tan
t   s i r e n   W i l l   i t   g o   f a
s t   o r   s l o w ? E x p l a i n   A   p e r
s o n   s tan d i n g   n e a r   a   r a i l w
a y   l i n e   h e a r s   t w o   d i s t i n
c t   s o u n d s   o f a n   a p p r o a c h i n g
  t r a i n   T h e   t i m e   i n t e r v a l
  b e t w e e n   t h e s e   s o u n d s   i s
  2   s   H o w   m u c h   i s   t h
e   d i s tan c e   o f   t h e   t r a i n ? V
e l o c i t y   o f   s o u n d   i n   a i r =
  340   r n s - l   V e l o c i t y   o f
  s o u n d   i n   S t e e l   =   16
  t i m e s   v e l o c i t y   o f   s o u n d
  i n   a i r

Anshu Agrawal · Accepted Answer

Dear student,

If the person standing near a railway line hears two distinct sounds of a train, then the sounds are - one travelling through steel and the another travelling through air.

Let the distance of train be d from the person.
speed of sound in air = 340 m/s
speed of sound in steel =

340 \times 16 = 5440 m / s

time taken by sound travelling through steel to reach the person = $t_s$
time taken by sound travelling through air to reach the person = $t_a$

t i m e = \frac{d i s \tan c e}{s p e e d} t_{s} = \frac{d}{5440} t_{a} = \frac{d}{340}

given that $t_a - t_s=2$

\frac{d}{340} - \frac{d}{5440} = 2 o r d (\frac{16 - 1}{5440}) = 2 d = \frac{2 \times 5440}{15} d = 725 m

Distance of train is 725m

Kindly post other questions in separate thread.

Regards