Please solve this question (0.1a-0.2c) (a+ c+ ac) Share with your friends Share 0 Komal Garg answered this Dear student,The given expression is (0.1 a-0.2 c)(a+c+ac). So,(0.1 a-0.2 c)(a+c+ac)= 0.1 a(a+c+ ac) - 0.2 c(a+c+ac) = 0.1 a²+ 0.1 ac+ 0.1 a²c - 0.2 ac- 0.2 c²- 0.2 a c² [using distributive property as well as xm×xn=xm+n] = 0.1 a² - 0.2 c² + 0.1 ac - 0.2 ac +0.1 a²c-0.2 a c²[Adding and subtracting like terms] = 0.1 a² - 0.2 c² -0.1 ac +0.1 a²c- 0.2 a c²Regards 0 View Full Answer
