Please solve this question Please solve this question (c) A BCD and BCFE a!-e parallelograms. If area ortriangle EBC = 480 AB = 40 Cin and BC = 30 cm, calculate: (iii) area Df parallelogram ABCD area of parallelogram BCFE length of altitude from area of A ECF. c Share with your friends Share 0 Rashi Lokwani answered this Dear Student, Ar(∆EBC) = 480 cm2AB = 40 cmBC = 30 cm(i) area of parallelogram ABCD:If a triangle and a parallelogram are on the same base and between the same parallels, then the area of triangle is equal to half the area of the parallelogram.∆EBC and parallelogram ABCD lie between the same parallel lines(AD and BC) and on the same base BCSo,ar(∆EBC) =12 ar(ABCD)ar(ABCD) = 2ar(∆EBC) = 2×480 = 960 cm2(ii)area of parallelogram BCEF:Parallelograms on same base and between same parallels have same area.So, ar(BCEF) = ar(ABCD) = 960 cm2(iii)length of altitude from A on CD:Area of parallelogram = Base × HeightAB = CD = 40 cm (Opposite sides of a parallelogram are equal)Let the altitude from A on CD be AO.When CD is the base of parallelogram ABCD:Area of parallelogram ABCD = CD × AO960 = 40 ×AOAO = 96040AO = 24 cmSo, length of altitude from A on CD = 24 cm(iv) area of ∆ECFIf a triangle and a parallelogram are on the same base and between the same parallels, then the area of triangle is equal to half the area of the parallelogram.∆ECF and parallelogram BCFE lie between the same parallel lines(EF and BC) and on the same base EFSo,ar(∆ECF) =12 ar(BCFE) = 12×960 = 480 cm2Ar(∆EBC) = 480 cm2AB = 40 cmBC = 30 cm(i) area of parallelogram ABCD:If a triangle and a parallelogram are on the same base and between the same parallels, then the area of triangle is equal to half the area of the parallelogram.∆EBC and parallelogram ABCD lie between the same parallel lines(AD and BC) and on the same base BCSo,ar(∆EBC) =12 ar(ABCD)ar(ABCD) = 2ar(∆EBC) = 2×480 = 960 cm2(ii)area of parallelogram BCEF:Parallelograms on same base and between same parallels have same area.So, ar(BCEF) = ar(ABCD) = 960 cm2(iii)length of altitude from A on CD:Area of parallelogram = Base × HeightAB = CD = 40 cm (Opposite sides of a parallelogram are equal)Let the altitude from A on CD be AO.When CD is the base of parallelogram ABCD:Area of parallelogram ABCD = CD × AO960 = 40 ×AOAO = 96040AO = 24 cmSo, length of altitude from A on CD = 24 cm(iv) area of ∆ECFIf a triangle and a parallelogram are on the same base and between the same parallels, then the area of triangle is equal to half the area of the parallelogram.∆ECF and parallelogram BCFE lie between the same parallel lines(EF and BC) and on the same base EFSo,ar(∆ECF) =12 ar(BCFE) = 12×960 = 480 cm2 Regards 0 View Full Answer
