Please solve this seperately

Please solve this seperately 3x-2 (xi) Xit

Dear student

(xii) x - \frac{x - 1}{2} = 1 - \frac{x - 2}{3} \Rightarrow \frac{2 x - x + 1}{2} = \frac{3 - x + 2}{3} \Rightarrow \frac{x + 1}{2} = \frac{5 - x}{3} \Rightarrow 3 (x + 1) = 2 (5 - x) \Rightarrow 3 x + 3 = 10 - 2 x \Rightarrow 3 x + 2 x = 10 - 3 \Rightarrow 5 x = 7 \Rightarrow x = \frac{7}{5}

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