Please solve this ::

The number of integers satisfying the inequality log 1 2 2 x + 4 log 2 x < 2 4 - log 16 x 4  are
(A) 2
(B) 3
(C) 4
(D) 5

Dear student,
log12x=-log2xlog2x=12logxlog16x4=44log2x=log2xPut log2x=tHence the inequality becomest2+2t<24-tSince LHS>0We have 4-t>0t<4Squaring both sides we gett2+2t<216+t2-8tt2-18t+32>0t-92>49As t<4we have t-9<-7t<2Also t2+2t0tt+20t(-,-2][0,)Hence t(-,-2][0,2)x(0,14][1,4)Regards

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