Dear student Given: x+y=8xy=334=154We know that x+y2=x2+y2+2xy82=x2+y2+2×15464=x2+y2+152x2+y2=64-152=1132So, 3x2+y2=3×1132=3392Also we know that x-y2=x2+y2-2xy x-y2=1132-2154=1132-152=49So, x-y=±7Similarly try third part Regards

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Given : x + y = 8 xy = 3 \frac{3}{4} = \frac{15}{4} We know that {(x + y)}^{2} = x^{2} + y^{2} + 2 xy 8^{2} = x^{2} + y^{2} + (2 \times \frac{15}{4}) 64 = x^{2} + y^{2} + \frac{15}{2} x^{2} + y^{2} = 64 - \frac{15}{2} = \frac{113}{2} So, 3 (x^{2} + y^{2}) = 3 \times \frac{113}{2} = \frac{339}{2} Also we know that {(x - y)}^{2} = x^{2} + y^{2} - 2 xy {(x - y)}^{2} = \frac{113}{2} - 2 (\frac{15}{4}) = \frac{113}{2} - \frac{15}{2} = 49 So, x - y = \pm 7 Similarly try third part .

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