Please solve xxii part of the following question

Dear Student,Solution)       7p2q9r524pqr314p6q10r42=49p4q18r1064p3q3r3196p12q20r8=49×64×p4+3×q18+3×r10+3196p12q20r8{When bases are same , powers are added}=49×64×p7×q21×r13196p12q20r8=16×p7×q21×r13p12q20r8=16×p7-12×q21-20×r13-8=16p-5q1r5or=16qr5p5Regards!

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