Dear Student,A dentist uses a concave mirror to view magnified image of teeth Given,m=+4 (Erect image)We know,m=-did0 di=v and d0=u⇒4=-did0⇒di=-4d0 1We have,1f=1d0+1di⇒1f=1d0-14d0=4-14d0=34d0 Using equation 1⇒f=43doRegars

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D e a r S t u d e n t, A d e n t i s t u s e s a c o n c a v e m i r r o r t o v i e w m a g n i f i e d i m a g e o f t e e t h . G i v e n, m = + 4 (E r e c t i m a g e) W e k n o w, m = - \frac{d_{i}}{d_{0}} (d_{i} = v a n d d_{0} = u) \Rightarrow 4 = - \frac{d_{i}}{d_{0}} \Rightarrow d_{i} = - 4 d_{0} . . . . . . . . (1) W e h a v e, \frac{1}{f} = \frac{1}{d_{0}} + \frac{1}{d_{i}} \Rightarrow \frac{1}{f} = \frac{1}{d_{0}} - \frac{1}{4 d_{0}} = \frac{4 - 1}{4 d_{0}} = \frac{3}{4 d_{0}} . . . . . . . . . . . . . . (U \sin g e q u a t i o n 1) \Rightarrow f = \frac{4}{3} d_{o} R e g a r s

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