Dear Student, Balanced chemical reaction is :2MnI2(s) +13F2(g) → 2MnF3 + 4IF5Therefore, 2×309 g MnI2 ≡ 13×38 g F212 g MnI2 ≡13×382×309×12- 9 59 gActual requirement of F2= 9 59×10075= 12 78 g

Pll;14!!!

Pll;14!!! Of bivalent lead ions in a sample Of polluted water that also contai nitöate ions is determined by adding solid sulphate (Me = 142 gmol•') to exactly 500 mL of •ter. Calculate the molarity of lead ions if 0.35$(9 pf sodium sulphate was needed for cornpMe recipitation of lead ions as sulphate. I . Sulphuric acid reacts with sodium hydroxide as follows: H2S04 + 2NaöH -i Na2SOi + 2H20 When 1 L Of 0.1M sulphuric acid solution is allowed to react with IL of 0.1M sodium hydroxide Olution, what is the amount of sodium sulphate formed and its molarity in the solution? If hpemoglobin (molecular weight = 67200) contains 0.33% of iron by weight, then what is the ,ntfmber of iron atoms present in one molecule of haemoglobin? X and Y are two elements which form X2Y3 and X3Y4. If 0.20 mol Of X2Y3 weighs 32.0g and 0.4 mol of weighs 92.8g, what are the atomic masses of X and Y? 3. What will be the composition of residual mixture if 30 g of Mg combines with 30 g of oxygen? 4. Manganese trifluoride can be prepared by the following reaction: Mn12(s) What is the minimum number of grams of F2 that must be used to react with 12.0g of Mn12 if verall yield of MnF3 is no more than 75%? . How much quantity of zinc will have to be reacted with excess of diltute HO solution produce sufficient hydrogen gas for completely reacting with the oxygen obtained by decomposing 5.104g Of potassium chlorate?

Dear Student,

Balanced chemical reaction is : 2 {MnI}_{2} (s) + 13 F_{2} (g) \to 2 {MnF}_{3} + 4 {IF}_{5} Therefore, 2 \times 309 g {MnI}_{2} \equiv 13 \times 38 g F_{2} 12 g {MnI}_{2} \equiv \frac{13 \times 38}{2 \times 309} \times 12 - 9.59 g Actual requirement of F_{2} = 9.59 \times \frac{100}{75} = 12.78 g

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