plllz help me for question no. 62!!!

Dear Student, The given series is A . P . whose nth term is (\frac{n}{x}) + y, Hence, First term, a = \frac{1}{x} + y Difference, d = (\frac{2}{x} + y) - (\frac{1}{x} + y) = \frac{1}{x} Sum of r terms = \frac{r}{2} (2 a + (r - 1) d) = \frac{r}{2} [2 (\frac{1}{x} + y) + (r - 1) \frac{1}{x}] = \frac{r}{2} [\frac{2}{x} + 2 y + \frac{r}{x} - \frac{1}{x}] = \frac{r}{2} [\frac{1}{x} + 2 y + \frac{r}{x}] = \frac{r}{2} [\frac{(r + 1)}{x} + 2 y] = \frac{r (r + 1)}{2 x} + ry Regards

plllz help me for question no. 62!!! ​