Pls ans following urgently dear experts: Q. A micrometer screw gauge has a negative error of 0.008 cm. While measuring the diameter of a wire, the reading on the main scale is 3 divisions and the 24th circular scale division coincides with the baseline. If the number of divisions on the main scale are 20 and circular scale has 100 divisions, calculate the: (a) pitch of the screw gauge. [Ans. 0.1 cm] (b) least count of the screw gauge. [Ans. 0.001 cm] (c) observed diameter of the wire. [Ans. 0.174 cml (d) corrected diameter of the wire. [Ans. 0.182 cm] Share with your friends Share 1 Decoder_2 answered this Dear Student, Please find the solution to the asked query Pitch = 0.1cm or 1mmLeast count = pitchTotal dividsion on the circular scale = 0.1100 = 0.001 cmObserved reading = Linear Scale Reading + no. of divisions on the circular scale × least countObserved reading = 3mm + 24×0.001 = 3.024 mmZero Error = - 8×0.001 = -0.008 mmActual reading = Observed reading - zero errorActual Reading = 3.024 -(-0.008) = 3.032 mm Regards 1 View Full Answer